C Program To Count Number Of Occurrence Of Characters In A String

               Program To count Number Of Occurrence

                      Of Characters In A String
Logic Applied:-
User Enters A String ,After that A While Loop Is For Looping Till Last Character In A String,
In The Next Line An if condition is for checking characters from A To Z,Now We Simply Count Characters /by Increment Operator
And Finally Print The Character Whose Value is At-least 1
Source Code:-
#include <stdio.h>
 #include <string.h> 
int main() 
{ 
char string[100]; 
int c = 0, count[26] = {0};
 printf("Enter a string\n"); 
gets(string); 
while (string[c] != '\0')
 { /** Considering characters from 'a' to 'z' only  ignoring others */ 
if (string[c] >= 'a' && string[c] <= 'z') 
count[string[c]-'a']++; 
c++; 
} 
for (c = 0; c < 26; c++) 
{ 
/** Printing only those characters whose count is at least 1 */
 if (count[c] != 0)
 printf("%c occurs %d times in the entered string.\n",c+'a',count[c]); 
} 
return 0; 

}  

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